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Question 5 of 375
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Drag & Drop Scenario
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172.28.228.144/18 172.28.192.1-172.28.255.254 172.28.228.144/21 172.28.224.1-172.28.255.254 172.28.228.144/23 172.28.228.1-172.28.255.254 172.28.228.144/25 172.28.228.129-172.28.228.254 172.28.228.144/29 172.28.228.145-172.28.228.254
I think the easiest way to solve this question is to find how much host are there in right hand side in usable host address range By using that number of host we can easily map with left hand side like for example /25 means 126 hosts per subnet now search which ranges has 126 hosts . This way would be much faster than any other way
Given Subnet Matching Usable Host Range 172.28.228.144/18 172.28.192.1 - 172.28.255.254 172.28.228.144/21 172.28.224.1 - 172.28.231.254 172.28.228.144/23 172.28.228.1 - 172.28.229.254 172.28.228.144/25 172.28.228.129 - 172.28.228.254 172.28.228.144/29 172.28.228.145 - 172.28.228.150